Optimal. Leaf size=129 \[ \frac{4 i f^2 \text{PolyLog}\left (2,i e^{i (c+d x)}\right )}{a d^3}-\frac{4 f (e+f x) \log \left (1-i e^{i (c+d x)}\right )}{a d^2}+\frac{(e+f x)^2 \cot \left (\frac{c}{2}+\frac{d x}{2}+\frac{\pi }{4}\right )}{a d}+\frac{i (e+f x)^2}{a d}+\frac{(e+f x)^3}{3 a f} \]
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Rubi [A] time = 0.257387, antiderivative size = 129, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 8, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.308, Rules used = {4515, 32, 3318, 4184, 3717, 2190, 2279, 2391} \[ \frac{4 i f^2 \text{PolyLog}\left (2,i e^{i (c+d x)}\right )}{a d^3}-\frac{4 f (e+f x) \log \left (1-i e^{i (c+d x)}\right )}{a d^2}+\frac{(e+f x)^2 \cot \left (\frac{c}{2}+\frac{d x}{2}+\frac{\pi }{4}\right )}{a d}+\frac{i (e+f x)^2}{a d}+\frac{(e+f x)^3}{3 a f} \]
Antiderivative was successfully verified.
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Rule 4515
Rule 32
Rule 3318
Rule 4184
Rule 3717
Rule 2190
Rule 2279
Rule 2391
Rubi steps
\begin{align*} \int \frac{(e+f x)^2 \sin (c+d x)}{a+a \sin (c+d x)} \, dx &=\frac{\int (e+f x)^2 \, dx}{a}-\int \frac{(e+f x)^2}{a+a \sin (c+d x)} \, dx\\ &=\frac{(e+f x)^3}{3 a f}-\frac{\int (e+f x)^2 \csc ^2\left (\frac{1}{2} \left (c+\frac{\pi }{2}\right )+\frac{d x}{2}\right ) \, dx}{2 a}\\ &=\frac{(e+f x)^3}{3 a f}+\frac{(e+f x)^2 \cot \left (\frac{c}{2}+\frac{\pi }{4}+\frac{d x}{2}\right )}{a d}-\frac{(2 f) \int (e+f x) \cot \left (\frac{c}{2}+\frac{\pi }{4}+\frac{d x}{2}\right ) \, dx}{a d}\\ &=\frac{i (e+f x)^2}{a d}+\frac{(e+f x)^3}{3 a f}+\frac{(e+f x)^2 \cot \left (\frac{c}{2}+\frac{\pi }{4}+\frac{d x}{2}\right )}{a d}-\frac{(4 f) \int \frac{e^{2 i \left (\frac{c}{2}+\frac{d x}{2}\right )} (e+f x)}{1-i e^{2 i \left (\frac{c}{2}+\frac{d x}{2}\right )}} \, dx}{a d}\\ &=\frac{i (e+f x)^2}{a d}+\frac{(e+f x)^3}{3 a f}+\frac{(e+f x)^2 \cot \left (\frac{c}{2}+\frac{\pi }{4}+\frac{d x}{2}\right )}{a d}-\frac{4 f (e+f x) \log \left (1-i e^{i (c+d x)}\right )}{a d^2}+\frac{\left (4 f^2\right ) \int \log \left (1-i e^{2 i \left (\frac{c}{2}+\frac{d x}{2}\right )}\right ) \, dx}{a d^2}\\ &=\frac{i (e+f x)^2}{a d}+\frac{(e+f x)^3}{3 a f}+\frac{(e+f x)^2 \cot \left (\frac{c}{2}+\frac{\pi }{4}+\frac{d x}{2}\right )}{a d}-\frac{4 f (e+f x) \log \left (1-i e^{i (c+d x)}\right )}{a d^2}-\frac{\left (4 i f^2\right ) \operatorname{Subst}\left (\int \frac{\log (1-i x)}{x} \, dx,x,e^{2 i \left (\frac{c}{2}+\frac{d x}{2}\right )}\right )}{a d^3}\\ &=\frac{i (e+f x)^2}{a d}+\frac{(e+f x)^3}{3 a f}+\frac{(e+f x)^2 \cot \left (\frac{c}{2}+\frac{\pi }{4}+\frac{d x}{2}\right )}{a d}-\frac{4 f (e+f x) \log \left (1-i e^{i (c+d x)}\right )}{a d^2}+\frac{4 i f^2 \text{Li}_2\left (i e^{i (c+d x)}\right )}{a d^3}\\ \end{align*}
Mathematica [A] time = 1.25245, size = 213, normalized size = 1.65 \[ \frac{\frac{12 f (\cos (c)+i \sin (c)) \left (\frac{f (\cos (c)-i (\sin (c)+1)) \text{PolyLog}(2,-\sin (c+d x)-i \cos (c+d x))}{d^2}-\frac{(\sin (c)+i \cos (c)+1) (e+f x) \log (\sin (c+d x)+i \cos (c+d x)+1)}{d}+\frac{(\cos (c)-i \sin (c)) (e+f x)^2}{2 f}\right )}{d (\cos (c)+i (\sin (c)+1))}-\frac{6 \sin \left (\frac{d x}{2}\right ) (e+f x)^2}{d \left (\sin \left (\frac{c}{2}\right )+\cos \left (\frac{c}{2}\right )\right ) \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )}+x \left (3 e^2+3 e f x+f^2 x^2\right )}{3 a} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.108, size = 282, normalized size = 2.2 \begin{align*}{\frac{{f}^{2}{x}^{3}}{3\,a}}+{\frac{fe{x}^{2}}{a}}+{\frac{{e}^{2}x}{a}}+2\,{\frac{{f}^{2}{x}^{2}+2\,fex+{e}^{2}}{da \left ({{\rm e}^{i \left ( dx+c \right ) }}+i \right ) }}+4\,{\frac{f\ln \left ({{\rm e}^{i \left ( dx+c \right ) }} \right ) e}{a{d}^{2}}}-4\,{\frac{f\ln \left ({{\rm e}^{i \left ( dx+c \right ) }}+i \right ) e}{a{d}^{2}}}+{\frac{2\,i{f}^{2}{x}^{2}}{da}}+{\frac{4\,i{f}^{2}cx}{a{d}^{2}}}+{\frac{2\,i{f}^{2}{c}^{2}}{{d}^{3}a}}-4\,{\frac{{f}^{2}\ln \left ( 1-i{{\rm e}^{i \left ( dx+c \right ) }} \right ) x}{a{d}^{2}}}-4\,{\frac{{f}^{2}\ln \left ( 1-i{{\rm e}^{i \left ( dx+c \right ) }} \right ) c}{{d}^{3}a}}+{\frac{4\,i{f}^{2}{\it polylog} \left ( 2,i{{\rm e}^{i \left ( dx+c \right ) }} \right ) }{{d}^{3}a}}-4\,{\frac{{f}^{2}c\ln \left ({{\rm e}^{i \left ( dx+c \right ) }} \right ) }{{d}^{3}a}}+4\,{\frac{{f}^{2}c\ln \left ({{\rm e}^{i \left ( dx+c \right ) }}+i \right ) }{{d}^{3}a}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.8965, size = 545, normalized size = 4.22 \begin{align*} \frac{d^{3} f^{2} x^{3} + 3 \, d^{3} e f x^{2} + 3 \, d^{3} e^{2} x - 6 i \, d^{2} e^{2} -{\left (12 \, d e f \cos \left (d x + c\right ) + 12 i \, d e f \sin \left (d x + c\right ) + 12 i \, d e f\right )} \arctan \left (\sin \left (d x + c\right ) + 1, \cos \left (d x + c\right )\right ) +{\left (12 \, d f^{2} x \cos \left (d x + c\right ) + 12 i \, d f^{2} x \sin \left (d x + c\right ) + 12 i \, d f^{2} x\right )} \arctan \left (\cos \left (d x + c\right ), \sin \left (d x + c\right ) + 1\right ) -{\left (i \, d^{3} f^{2} x^{3} +{\left (3 i \, d^{3} e f - 6 \, d^{2} f^{2}\right )} x^{2} - 3 \,{\left (-i \, d^{3} e^{2} + 4 \, d^{2} e f\right )} x\right )} \cos \left (d x + c\right ) +{\left (12 \, f^{2} \cos \left (d x + c\right ) + 12 i \, f^{2} \sin \left (d x + c\right ) + 12 i \, f^{2}\right )}{\rm Li}_2\left (i \, e^{\left (i \, d x + i \, c\right )}\right ) -{\left (6 \, d f^{2} x + 6 \, d e f +{\left (-6 i \, d f^{2} x - 6 i \, d e f\right )} \cos \left (d x + c\right ) + 6 \,{\left (d f^{2} x + d e f\right )} \sin \left (d x + c\right )\right )} \log \left (\cos \left (d x + c\right )^{2} + \sin \left (d x + c\right )^{2} + 2 \, \sin \left (d x + c\right ) + 1\right ) +{\left (d^{3} f^{2} x^{3} + 3 \,{\left (d^{3} e f + 2 i \, d^{2} f^{2}\right )} x^{2} +{\left (3 \, d^{3} e^{2} + 12 i \, d^{2} e f\right )} x\right )} \sin \left (d x + c\right )}{-3 i \, a d^{3} \cos \left (d x + c\right ) + 3 \, a d^{3} \sin \left (d x + c\right ) + 3 \, a d^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.98595, size = 1378, normalized size = 10.68 \begin{align*} \frac{d^{3} f^{2} x^{3} + 3 \, d^{2} e^{2} + 3 \,{\left (d^{3} e f + d^{2} f^{2}\right )} x^{2} + 3 \,{\left (d^{3} e^{2} + 2 \, d^{2} e f\right )} x +{\left (d^{3} f^{2} x^{3} + 3 \, d^{2} e^{2} + 3 \,{\left (d^{3} e f + d^{2} f^{2}\right )} x^{2} + 3 \,{\left (d^{3} e^{2} + 2 \, d^{2} e f\right )} x\right )} \cos \left (d x + c\right ) +{\left (6 i \, f^{2} \cos \left (d x + c\right ) + 6 i \, f^{2} \sin \left (d x + c\right ) + 6 i \, f^{2}\right )}{\rm Li}_2\left (i \, \cos \left (d x + c\right ) - \sin \left (d x + c\right )\right ) +{\left (-6 i \, f^{2} \cos \left (d x + c\right ) - 6 i \, f^{2} \sin \left (d x + c\right ) - 6 i \, f^{2}\right )}{\rm Li}_2\left (-i \, \cos \left (d x + c\right ) - \sin \left (d x + c\right )\right ) - 6 \,{\left (d e f - c f^{2} +{\left (d e f - c f^{2}\right )} \cos \left (d x + c\right ) +{\left (d e f - c f^{2}\right )} \sin \left (d x + c\right )\right )} \log \left (\cos \left (d x + c\right ) + i \, \sin \left (d x + c\right ) + i\right ) - 6 \,{\left (d f^{2} x + c f^{2} +{\left (d f^{2} x + c f^{2}\right )} \cos \left (d x + c\right ) +{\left (d f^{2} x + c f^{2}\right )} \sin \left (d x + c\right )\right )} \log \left (i \, \cos \left (d x + c\right ) + \sin \left (d x + c\right ) + 1\right ) - 6 \,{\left (d f^{2} x + c f^{2} +{\left (d f^{2} x + c f^{2}\right )} \cos \left (d x + c\right ) +{\left (d f^{2} x + c f^{2}\right )} \sin \left (d x + c\right )\right )} \log \left (-i \, \cos \left (d x + c\right ) + \sin \left (d x + c\right ) + 1\right ) - 6 \,{\left (d e f - c f^{2} +{\left (d e f - c f^{2}\right )} \cos \left (d x + c\right ) +{\left (d e f - c f^{2}\right )} \sin \left (d x + c\right )\right )} \log \left (-\cos \left (d x + c\right ) + i \, \sin \left (d x + c\right ) + i\right ) +{\left (d^{3} f^{2} x^{3} - 3 \, d^{2} e^{2} + 3 \,{\left (d^{3} e f - d^{2} f^{2}\right )} x^{2} + 3 \,{\left (d^{3} e^{2} - 2 \, d^{2} e f\right )} x\right )} \sin \left (d x + c\right )}{3 \,{\left (a d^{3} \cos \left (d x + c\right ) + a d^{3} \sin \left (d x + c\right ) + a d^{3}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{e^{2} \sin{\left (c + d x \right )}}{\sin{\left (c + d x \right )} + 1}\, dx + \int \frac{f^{2} x^{2} \sin{\left (c + d x \right )}}{\sin{\left (c + d x \right )} + 1}\, dx + \int \frac{2 e f x \sin{\left (c + d x \right )}}{\sin{\left (c + d x \right )} + 1}\, dx}{a} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (f x + e\right )}^{2} \sin \left (d x + c\right )}{a \sin \left (d x + c\right ) + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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